Senin, 16 November 2009

latihan tugas

Latihan Tugas Pengantar Tekhnologi Informasi
Lengkapi
Decimal Biner Octal hexadesimal
325 101000101 505 145
123 1111011 173 7 B
85 1010101 125 55
411 110011011 633 19

Langkah-langkah
1.)325 (Desimal) :101000101 Biner(2)
325
2-------1
162
2-------0
81
2-------1
40
2------0
20
2------0
10
2------0
5
2------1
2
2-----0
1

_325 Desimal = 505 oktal(8)
325
8-------5
40
8------0
5

_325 Desimal = 145 Hexadesimal (16)
325
16-----5
20
16----4
1

2.) a. 2^6 2^5 2^4 2^3 2^2 2^1 2^0
64*1 32*1 16*1 8*1 4*0 2*1 1*1
64 32 16 8 0 2 1

64+32+16+8+2+1 = 123


b.123 Desimal = 173 oktal
123
8---------3
15
8--------7
1

c. 123 Desimal = 7 B hexadesimal
123
16------11
7

3.) a. 125 oktal = 85 desimal

8^2 8^1 8^0
64 8 1
1 2 5
64 16 5
Desimal =64+16+5 = 85

b.85 Desimal =1010101 biner (2)
85
2------1
42
2-----0
21
2-----1
10
2------0
5
2------1
2
2-----0
1


c. 85 Desimal =55 hexadesimal
85
16-----5
5


4.) a. 19 B hexadesimal = 411 desimal

16^2 16^1 16^0
256 16 1
1 9 B
1 9 11
256 144 11


b. 411 hexadesimal = 110011011 biner
411
2-------1
205
2------1
102
2-------0
51
2-------1
25
2-------1
12
2------0
6
2------0
3
2-------1
1

c. 411 desimal = 633 oktal
411
8--------3
51
8-------3
6

1 komentar:

  1. hayoooo berapkah bilangan biner dari 256?
    hahaha gampang nih...
    silakan dijawab!!

    BalasHapus